| commit | 4c04f96b7d0f50193642541d1cf9911dbbb5f6bc | [log] [tgz] |
|---|---|---|
| author | Philipp Hagemeister <phihag@phihag.de> | Sun Oct 16 22:28:08 2016 |
| committer | Philipp Hagemeister <phihag@phihag.de> | Sun Oct 16 22:28:08 2016 |
| tree | 2b5b628ceff97048155db35ce3343cbbb6469ea7 | |
| parent | 2e605b37284d8dee5af1fa7a5e5665e0ae08d2e4 [diff] |
make one more test ready for Python 2.6
Python 3.3+'s ipaddress for Python 2.6, 2.7, 3.2.
Note that as in Python 3.3+ you must use character strings and not byte strings for textual IP address representations:
>>> from __future__ import unicode_literals >>> ipaddress.ip_address('1.2.3.4') IPv4Address(u'1.2.3.4')
or
>>> ipaddress.ip_address(u'1.2.3.4') IPv4Address(u'1.2.3.4')
but not:
>>> ipaddress.ip_address(b'1.2.3.4') Traceback (most recent call last): File "<stdin>", line 1, in <module> File "ipaddress.py", line 163, in ip_address ' a unicode object?' % address) ipaddress.AddressValueError: '1.2.3.4' does not appear to be an IPv4 or IPv6 address. Did you pass in a bytes (str in Python 2) instead of a unicode object?