commit | e98c02a4987a6cba3c0bc225c2115cf631ea9b33 | [log] [tgz] |
---|---|---|
author | Philipp Hagemeister <phihag@phihag.de> | Thu Jul 16 21:08:08 2015 |
committer | Philipp Hagemeister <phihag@phihag.de> | Thu Jul 16 21:08:08 2015 |
tree | 5979cd3f71a3b36ef299fd86fac750ac9b3b5e62 | |
parent | d13b28c6ba1525fa56b81348618443795da63291 [diff] |
release 1.0.14
Python 3.3+'s ipaddress for Python 2.6, 2.7, 3.2.
Note that as in Python 3.3+ you must use character strings and not byte strings for textual IP address representations:
>>> from __future__ import unicode_literals >>> ipaddress.ip_address('1.2.3.4') IPv4Address(u'1.2.3.4')
or
>>> ipaddress.ip_address(u'1.2.3.4') IPv4Address(u'1.2.3.4')
but not:
>>> ipaddress.ip_address(b'1.2.3.4') Traceback (most recent call last): File "<stdin>", line 1, in <module> File "ipaddress.py", line 163, in ip_address ' a unicode object?' % address) ipaddress.AddressValueError: '1.2.3.4' does not appear to be an IPv4 or IPv6 address. Did you pass in a bytes (str in Python 2) instead of a unicode object?