blob: 2e270fb24d83a0799503cd5008fba92bce1397a8 [file] [log] [blame]
/*
* Copyright (C) 2010 Google Inc.
*
* This program is free software; you can redistribute it and/or
* modify it under the terms of the GNU General Public License
* as published by the Free Software Foundation; either version 2
* of the License, or (at your option) any later version.
*
* This program is distributed in the hope that it will be useful,
* but WITHOUT ANY WARRANTY; without even the implied warranty of
* MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
* GNU General Public License for more details.
*
* You should have received a copy of the GNU General Public License
* along with this program; if not, write to the Free Software
* Foundation, Inc., 51 Franklin Street, Fifth Floor, Boston, MA 02110-1301, USA
*
* math.c: implementations of some numerical utilities
*/
#include <stdio.h>
#include <stdlib.h>
#include <inttypes.h>
#include <unistd.h>
#include <string.h>
#include <fcntl.h>
#include <sys/stat.h>
#include <string.h>
#include <sys/types.h>
#include "lib/math.h"
/*
* ctz - count trailing zeros
*
* @u: Bit vector to count trailing zeros in.
*
* Counts bit positions of lower significance than that of the least significant
* bit set. Based off of an algorithm from:
* http://graphics.stanford.edu/~seander/bithacks.html
*
* returns count of trailing zeros
*/
int ctz(unsigned long long int u)
{
int num_zeros;
union {
float f;
uint32_t i;
} alias;
if (u == 0) /* The algorithm will return -127 on this condition */
return 0;
alias.f = (float)(u & (~u + 1));
num_zeros = (alias.i >> 23) - 0x7f;
return num_zeros;
}
/*
* logbase2 - Return log base 2 of the absolute value of n (2^r = abs(n)) of an
* integer by using a cast to float method (Requires IEEE-754).
*
* Note: We could just use log2() but that would require messing with our
* compilation and linking options and hacking around the n = 0 case in other
* areas of the code.
*
* @n: The number to find the log base 2 of
*
* returns log2(n) if successful
*/
int logbase2(int n)
{
float f;
int r;
/* This algorithm fails (Returns negative infinity) if n = 0. We'll be
* using it mostly in the context of CPU numbers, so we'll take the
* liberty of returning 0 instead of aborting */
if (n == 0)
return 0;
f = (float)n;
memcpy(&r, &f, sizeof(n));
/* Isolate exponent and un-bias the exponent (Subtract +128) */
r = ((r & 0x7F800000) >> 23) - 0x80;
return r + 1;
}
/*
* rolling8_csum - Bytewise rolling summation "checksum" of a buffer
*
* @buf: buffer to sum
* @len: length of buffer
*/
uint8_t rolling8_csum(uint8_t *buf, size_t len)
{
size_t i;
uint8_t sum = 0;
for (i = 0; i < len; ++i)
sum += buf[i];
return sum;
}
/*
* zero8_csum - Calculates 8-bit zero-sum checksum
*
* @buf: input buffer
* @len: length of buffer
*
* The summation of the bytes in the array and the csum will equal zero
* for 8-bit data size.
*
* returns checksum to indicate success
*/
uint8_t zero8_csum(uint8_t *buf, size_t len)
{
uint8_t *u = buf;
uint8_t csum = 0;
while (u < buf + len) {
csum += *u;
u++;
}
return (0x100 - csum);
}