| commit | 0a2411340c9ddf193477ee9b26aebf4c6d13f65b | [log] [tgz] |
|---|---|---|
| author | Philipp Hagemeister <phihag@phihag.de> | Fri Oct 18 00:44:42 2019 |
| committer | Philipp Hagemeister <phihag@phihag.de> | Fri Oct 18 00:44:42 2019 |
| tree | 5137284ddb46c537361de09e3f726b6b65829a3a | |
| parent | 3240fdf99e3e62874e862987cd7f8cc1885e613a [diff] |
lint: Make sure all lines are <= 80 chars long
Python 3.3+'s ipaddress for Python 2.6, 2.7, 3.2.
Note that as in Python 3.3+ you must use character strings and not byte strings for textual IP address representations:
>>> from __future__ import unicode_literals >>> ipaddress.ip_address('1.2.3.4') IPv4Address(u'1.2.3.4')
or
>>> ipaddress.ip_address(u'1.2.3.4') IPv4Address(u'1.2.3.4')
but not:
>>> ipaddress.ip_address(b'1.2.3.4') Traceback (most recent call last): File "<stdin>", line 1, in <module> File "ipaddress.py", line 163, in ip_address ' a unicode object?' % address) ipaddress.AddressValueError: '1.2.3.4' does not appear to be an IPv4 or IPv6 address. Did you pass in a bytes (str in Python 2) instead of a unicode object?