commit | cf7f1781002658405e889a5e53854b0e15334bcf | [log] [tgz] |
---|---|---|
author | Philipp Hagemeister <phihag@phihag.de> | Fri Sep 09 10:29:34 2016 |
committer | Philipp Hagemeister <phihag@phihag.de> | Fri Sep 09 10:29:34 2016 |
tree | 476af2dd7da6135ec98b0d4c77bd3871b823029d | |
parent | 77c528007b90de88068df498726c574e8a86f497 [diff] | |
parent | ea9945d8b80552069aabddf197c7447953280d00 [diff] |
pull in current upstream version
Python 3.3+'s ipaddress for Python 2.6, 2.7, 3.2.
Note that as in Python 3.3+ you must use character strings and not byte strings for textual IP address representations:
>>> from __future__ import unicode_literals >>> ipaddress.ip_address('1.2.3.4') IPv4Address(u'1.2.3.4')
or
>>> ipaddress.ip_address(u'1.2.3.4') IPv4Address(u'1.2.3.4')
but not:
>>> ipaddress.ip_address(b'1.2.3.4') Traceback (most recent call last): File "<stdin>", line 1, in <module> File "ipaddress.py", line 163, in ip_address ' a unicode object?' % address) ipaddress.AddressValueError: '1.2.3.4' does not appear to be an IPv4 or IPv6 address. Did you pass in a bytes (str in Python 2) instead of a unicode object?