commit | dfe66fd09d51e50e81bb18dcbc0ff65db60fb714 | [log] [tgz] |
---|---|---|
author | Philipp Hagemeister <phihag@phihag.de> | Tue Jul 14 19:30:58 2015 |
committer | Philipp Hagemeister <phihag@phihag.de> | Tue Jul 14 19:30:58 2015 |
tree | cd236a3e0edcc3f19dd152da66f46ba5475d61f0 | |
parent | 98814961400d50e832722ab28628a574de252f5c [diff] |
release 1.0.12
Python 3.3+'s ipaddress for Python 2.6, 2.7, 3.2.
Note that as in Python 3.3+ you must use character strings and not byte strings for textual IP address representations:
>>> from __future__ import unicode_literals >>> ipaddress.ip_address('1.2.3.4') IPv4Address(u'1.2.3.4')
or
>>> ipaddress.ip_address(u'1.2.3.4') IPv4Address(u'1.2.3.4')
but not:
>>> ipaddress.ip_address(b'1.2.3.4') Traceback (most recent call last): File "<stdin>", line 1, in <module> File "ipaddress.py", line 163, in ip_address ' a unicode object?' % address) ipaddress.AddressValueError: '1.2.3.4' does not appear to be an IPv4 or IPv6 address. Did you pass in a bytes (str in Python 2) instead of a unicode object?